# Chapter 11 - Rational Expressions and Functions - 11-6 Inverse Variation - Practice and Problem-Solving Exercises - Page 691: 34

$y = 15$

#### Work Step by Step

Our equation for an inverse variation is $y = \frac{k}{x}$ or $xy = k$. We will use the second form of the equation to solve for k. We use the ordered pair (3,5) to solve for k, from which we know that $x = 3$ and $y = 5$. $3\times55 = k$ $15 = k$ So, $k = 15$ Therefore, our equation for the inverse variation is $y = \frac{15}{x}$ or $xy = 15$ Using the first form of the equation, $y = \frac{15}{x}$, we can use the x value of the second order pair to find our missing y value. $y = \frac{15}{1}$ $y = 15$

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