## Algebra 1

$x^2+3 =g(x)$ vertex and line of symmetry: $x=-b/2a$ $x=0/2*1 = 0$ $x=0$ $g(0) = 0^2+3$ $g(0) = 0+3 = 3$ $(0,3)$ One other point on the curve: $x=1$ $g(1)= 1^2+3$ $g(1) = 1+3 =4$ $(1,4)$