Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 11 - Rational Expressions and Functions - 11-6 Inverse Variation - Mixed Review - Page 692: 57

Answer

Please see the graph.
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Work Step by Step

$x^2+3 =g(x)$ vertex and line of symmetry: $x=-b/2a$ $x=0/2*1 = 0$ $x=0$ $g(0) = 0^2+3$ $g(0) = 0+3 = 3$ $(0,3)$ One other point on the curve: $x=1$ $g(1)= 1^2+3$ $g(1) = 1+3 =4$ $(1,4)$
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