Answer
Please see the graph.
Work Step by Step
$x^2+3 =g(x)$
vertex and line of symmetry:
$x=-b/2a$
$x=0/2*1 = 0$
$x=0$
$g(0) = 0^2+3$
$g(0) = 0+3 = 3$
$(0,3)$
One other point on the curve:
$x=1$
$g(1)= 1^2+3$
$g(1) = 1+3 =4$
$(1,4)$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 11 - Rational Expressions and Functions - 11-6 Inverse Variation - Mixed Review - Page 692: 57
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