## Algebra 1

$r = -1$
$2/r + 1/(r^2) + (r^2+r)/(r^3) = 1/r$ $r^3*(2/r + 1/(r^2) + (r^2+r)/(r^3) = 1/r)$ $2*r^3/r + 1*r^3/(r^2) + r^3*(r^2+r)/(r^3) = (1/r)*r^3$ $2*r^2 + r + (r^2+r) = r^2$ $2r^2 +r + r^2 +r = r^2$ $2r^2 + 2r = 0$ $2r(r+1)=0$ $2r=0$ $r=0$ (we can't have zero in the denominator, so this answer is invalid) $r+1=0$ $r=-1$ $r=-1$ $2/r + 1/(r^2) + (r^2+r)/(r^3) = 1/r$ $2/(-1) + 1/((-1)^2) + ((-1)^2+(-1))/((-1)^3) = 1/(-1)$ $-2 +(1/1) +(1-1)/-1 = -1$ $-2 + 1 +0 = -1$ $-2+1+0 = -1$ $-1 =-1$