Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 11 - Rational Expressions and Functions - 11-4 Adding and Subtracting Rational Expressions - Mixed Review - Page 677: 62



Work Step by Step

First square both sides: $x^2=5x+6$ Then move the $5x+6$ to the left-hand side to create a quadratic: $x^2-5x-6=0$ Use the quadratic formula to solve for possible values of $x$: The quadratic formula states that for a quadratic $ax^2+bx+c$, the two possible roots take the form $\frac{-b+\sqrt{b^2-4ac}}{2a}$ or $\frac{-b-\sqrt{b^2-4ac}}{2a}$. We see that the two possible roots of our equation are $\frac{5+\sqrt{49}}{2}=6$ and $\frac{5-\sqrt{49}}{2} = -1$. Looking back at our original equation, we see that $x$ is the square root of a number. Because the square root of a number cannot be negative, we see that $x=6$ is the only solution to this equation.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.