## Algebra 1

For $\frac{n-2}{2-n}$, we can factor out a negative from the denominator. $\frac{n-2}{2-n} = \frac{n-2}{-(-2+n)}=\frac{n-2}{-(n-2)}$ We can now cancel out the common factor $(n-2)$ $\frac{n-2}{-(n-2)}$ = -1