Algebra 1

$y=x^2-6$ shifted 3 units down Let $x=0$ $y=x^2-6$ $y=0^2-6$ $y=0-6$ $y=-6$ $(0,-6)$ would be shifted to $(0,-9)$ $y=x^2-b$ $-9=0^2-b$ $-9=0-b$ $b-9=0$ $b=9$ $y=x^2-9$