## Algebra 1

Using the point $(2,2)$, we can create two triangles and a rectangle to find the areas. The upper triangle has points at $(-4,2), (2,5)$, and $(2,2)$. The lower triangle has points at $(2,-2), (4,-2)$, and $(2,5)$. The points of the rectangle are $(4,-2), (2,2), (2,-2)$, and $(-4, -2)$. upper triangle: $5-2=3$ $2-(-4)=2+4=6$ lower triangle: $4-2=2$ $5-(-2)=5+2=7$ Rectangle: $4-(-4)=4+4=8$ $2-(-2)=2+2=4$ $1/2*(3*6)+1/2*(2*7)+8*4$ $1/2*18+1/2*14+32$ $9+7+32$ $16+32$ $48$