Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - Concept Byte - Distance and Midpoint Formulas: 6

Answer

$d=12.5$ M$(0,1\frac{1}{4})$

Work Step by Step

$d=\sqrt {(x_2-x_1)^2+(y_2-y_1)^2}$ $d=\sqrt {(6-(-6))^2+(-\frac{1}{2}-3)^2}$ $d=\sqrt {(12)^2+(-3\frac{1}{2})^2}$ $d=\sqrt {144+12.25}$ $d=\sqrt {156.25}$ $d=12.5$ M$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$ M$(\frac{-6+6}{2},\frac{3+(-\frac{1}{2})}{2})$ M$(\frac{0}{2},\frac{2\frac{1}{2}}{2})$ M$(0,1\frac{1}{4})$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.