## Algebra 1

$\sqrt {5x+6} +2 =0$ $x=-2/5$ is the extraneous solution
$\sqrt {5x+6} +2 =0$ $\sqrt {5x+6} =-2$ $(\sqrt {5x+6})^2 =(-2)^2$ $5x+6=4$ $5x=-2$ $5x/5=-2/5$ $x=-.4$ $\sqrt {5x+6} +2 =0$ $\sqrt {5*(-2/5)+6} +2 =0$ $\sqrt{-2+6} +2 =0$ $\sqrt {4} +2=0$ $2 + 2 \ne0$ $4 \ne 0$