Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-6 Trigonometric Ratios - Practice and Problem-Solving Exercises - Page 638: 32


x = 45

Work Step by Step

Use the Sine rule for the right triangle: $\frac{opposite}{hypotenuse}$ sin(x) = $\frac{3}{3*\sqrt{2}}$ Simplify the above equation sin(x) = $\frac{1}{\sqrt{2}}$ Because sin(45) = $\frac{1}{\sqrt{2}}$: x = 45 degrees
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