Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-5 Graphing Square Root Functions - Practice and Problem-Solving Exercises - Page 630: 50

Answer

(see graph)
1551063289

Work Step by Step

The computations below show some of the values of $x$ and $y$ in the given equation, $ y=\sqrt{2x}+3 .$ If $x=-1,$ then \begin{array}{l}\require{cancel} y=\sqrt{2(-1)}+3 \\ y=\sqrt{-2}+3 \\ y=\text{not a real number} \\\text{(*Note that the square root of negative numbers are imaginary numbers)} .\end{array} If $x=0,$ then \begin{array}{l}\require{cancel} y=\sqrt{2(0)}+3 \\ y=\sqrt{0}+3 \\ y=0+3 \\ y=3 .\end{array} If $x=0.5,$ then \begin{array}{l}\require{cancel} y=\sqrt{2(0.5)}+3 \\ y=\sqrt{1}+3 \\ y=1+3 \\ y=4 .\end{array} If $x=2,$ then \begin{array}{l}\require{cancel} y=\sqrt{2(2)}+3 \\ y=\sqrt{4}+3 \\ y=2+3 \\ y=5 .\end{array} If $x=4.5,$ then \begin{array}{l}\require{cancel} y=\sqrt{2(4.5)}+3 \\ y=\sqrt{9}+3 \\ y=3+3 \\ y=6 .\end{array} The results above are summarized in the table of values below and are used to graph the given function.
Small 1551063289
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.