Chapter 10 - Radical Expressions and Equations - 10-5 Graphing Square Root Functions - Practice and Problem-Solving Exercises - Page 629: 40

Domain: $(-infinity,4 ]$ Range: $(0, infinity)$

We can't take the square root of a negative number, so $8-2x=0$. $8-2x=0$ $8=2x$ $8/2 = 2x/2$ $x=4$ $x=3$ $y=\sqrt {8-2x}$ $y=\sqrt {8-2*3}$ $y=\sqrt {8-6}$ $y=\sqrt {2}$ $y= 1.414$ Since we can have negative values for the variable, the graph has a negative slope. This means that the maximum value of the function is infinity.