Answer
There will be no solution for the given equation.
Work Step by Step
Given Infomation :
$\sqrt 2r - 3 = r$ ------- eq1
By squaring the eq 1 we get
$2r- 3= r^{2}$ ---- eq 2
By simplifying the eq 2 on both sides we get,
$0=r^{2}-2r+3$ ----eq3
Now, by factoring the eq 3
$0=(r-3)(r+1)$
By using the zero product property
$r-3=$ -> r=3
$r+1$ -> r=-1
Now, By checking
At
r=3,
$\sqrt 2(3)-3=3$
$\sqrt 3\ne3$
r=-1
$\sqrt 2(-1)-3=-1$
$\sqrt -5\ne-1$
So Both are extraneous solutions.
Hence there are no solutions
