Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-5 Graphing Square Root Functions - Lesson Check - Page 628: 1


$(-3, infinity)$

Work Step by Step

We can't have the square root of a negative number, so $y$'s lowest value is 0. $0=\sqrt {x+3}$ $0^2=(\sqrt {x+3})^2$ $0= x+3$ $-3=x$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.