Answer
$-\frac{2\sqrt 3-4\sqrt 2}{5}$
Work Step by Step
You need to multiply the numerator and denominator by the conjugate which is $\sqrt 3-\sqrt 8$:
$\frac{2}{\sqrt 3+\sqrt 8}$$\times$$\frac{\sqrt 3-\sqrt 8}{\sqrt 3-\sqrt 8}$$=$$\frac{2\sqrt 3-2\sqrt 8}{-5}$
Now, simplify the radical:
$\frac{2\sqrt 3-2\sqrt 8}{-5}$=$\frac{2\sqrt 3-4\sqrt 2}{-5}$=$-\frac{2\sqrt 3-4\sqrt 2}{5}$
