## Algebra 1

$\frac{\sqrt2-3}{\sqrt2-3}$ $\frac{2(\sqrt2-3)}{2(\sqrt2-3)}$ $\frac{10(\sqrt2-3)}{10(\sqrt2-3)}$ All of these will be the same since any number divided by itself is 1.
$\frac{\sqrt2-3}{\sqrt2-3}*\frac1{\sqrt2+3}$ $\frac{\sqrt2-3}{2-9}$ $\frac{\sqrt2-3}{-7}$ $\frac{10(\sqrt2-3)}{10(\sqrt2-3)}*\frac1{\sqrt2+3}$ $\frac{10(\sqrt2-3)}{10*({2-9})}$ $\frac{\sqrt2-3}{{2-9}}$ $\frac{\sqrt2-3}{{-7}}$