## Algebra 1

Published by Prentice Hall

# Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Standardized Test Prep - Page 612: 80

H

#### Work Step by Step

Use cross multiplication to solve for b. $\frac{3}{b}=\frac{7}{8-b}\longrightarrow$ cross multiply $3(8-b)=7b\longrightarrow$ multiply using distributive property $24-3b=7b\longrightarrow$ add 3b to each side $24-3b+3b=7b+3b\longrightarrow$ add $24=10b\longrightarrow$ multiply each side by 10 $\frac{24}{10}=\frac{10b}{10}\longrightarrow$ reduce $\frac{12}{5}=b$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.