Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises - Page 612: 75


$(\sqrt x)^{2}$ = x $10b^{2} $

Work Step by Step

$(\sqrt x)^{2}$ = x $2b ( \sqrt 5b)^{2}$ = $2b ( \sqrt 5b) \times ( \sqrt 5b)$ Since ( \sqrt 5b) and ( \sqrt 5b) are under a square root we multiply them together under a square root = $2b ( \sqrt (5b \times 5b))$ = $2b ( \sqrt (25b^{2}))$ Square root of $25b^{2}$ is 5b because 5b x 5b = $25b^{2}$ = 2b ( 5b) We multiply the numbers together and variables together = $10b^{2} $
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