Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Lesson Check: 6

Answer

$\frac{\sqrt {3n}}{n}$

Work Step by Step

We rationalize the denominator. $\frac{\sqrt 6}{\sqrt {2n}}$ $\longrightarrow$ multiply top and bottom by $\sqrt {2n}$ $\frac{\sqrt 6}{\sqrt {2n}}\times\frac{\sqrt {2n}}{\sqrt {2n}}$ $=\frac{\sqrt {12n}}{2n}$ $=\frac{\sqrt {4\times3n}}{2n}$ $=\frac{2\sqrt {3n}}{2n}$ $=\frac{\sqrt {3n}}{n}$
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