Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-1 The Pythagorean Theorem - Practice and Problem-Solving Exercises - Page 604: 42



Work Step by Step

We can call the consecutive integers $a$, $a+1$ and $a+2$. Now using the pythagorean theorem, $a^2+(a+1)^2=(a+2)^2$ Expanding this, we get $2a^2+2a+1=a^2+4a+4$. When we simplify, we get $a^2-2a-3=0$. $(a-3)(a+1)=0$ so $a$ must equal $3$
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