Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-1 The Pythagorean Theorem - Lesson Check - Page 602: 1



Work Step by Step

In order to solve this equation, you need to use The Pythagorean Theorem, which is: $a^{2}+b^{2}=c^{2}$ Now when we replace the variables with numbers we get: $36^{2}+15^{2}=x^2$ (In this case, $x$ represents $c$) When you simplify this equation, you get: $1296+225=x^{2}$ When we simplify this further by adding the first two numbers, we get: $1521=x^2$ Finally, we can take the square root of both of these numbers: $\sqrt x^2=\sqrt1521$ Finally, we get our answer: $x=39$
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