## Algebra 1

x must be even since neither the other term nor the sum are fractional. $\underline x\ \ \ \ \underline{\frac{1}{2}x-5}$ $2\ \ \ \ \ \ -4$ $4\ \ \ \ \ \ -3$ $6\ \ \ \ \ \ -2$ $8\ \ \ \ \ \ -1\longrightarrow$ 8 is the solution