Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 1 - Foundations for Algebra - 1-6 Multiplying and Dividing Real Numbers - Practice and Problem-Solving Exercises - Page 44: 69



Work Step by Step

part 1 (-n)^3 So we want the greatest value of n to make the result a positive integer ending in 2. Part 2 (8)^3=8*8*8=512 (-(8))^3=(-8)*(-8)*(-8)=-512 First, we need a number that has a cube end in 2. So just go through and raise 0 through 9 to 3 and you'll see that 8 is 512. which has a 2 in the ones place. But if we plug in 8 for n, it is -512. This is because we are multiplying by -8, 3 times. Multiplying two negatives together gets rid of the negative, but multiplying that by another negative puts the negative back. part 3 (-(-8))^3=8^3=8*8*8=512 So, in order to get rid of that, we have to make n-8. -8 is the largest negative number that ends with 8, so -8 will be the answer.
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