## Algebra 1

a) substitute the given values $(x+y)^2=(1+0)^2=1^2=1$ $x^2+y^2=1^2+0^2=1+0=1$ b) substitute the given values $(x+y)^2=(1+2)^2=3^2=9$ $x^2+y^2=1^2+2^2=1+4=5$ c) Let x=2 and y=3 $(x+y)^2=(2+3)^2=5^2=25$ $x^2+y^2=2^2+3^2=4+9=13$ d) The claim is not correct because the result of simplifying the equations is not the same for every combination of values for x and y.