# Skills Handbook - Simplifying Fractions - Exercises - Page 801: 11

2

#### Work Step by Step

We can solve these problems by comparing the numerator and the denominator. The numerator in the first fraction is 50 times greater than the numerator in the second fraction, so we know that the denominator of the second fraction must be 1/50 as much as the denominator of the first fraction. Thus, we multiply 100 by 1/50 to find that the missing number is 2.

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