## Algebra 1: Common Core (15th Edition)

H; $95°F$
Substitute the value of the temperature in Celsius into the equation and solve for the value in Fahrenheit. $C=35$ $F=\frac{9}{5}C+32$ Therefore: $F=\frac{9\times35}{5}+32$ $F=\frac{9\times7}{1}+32$ $F=63+32$ $F=95$ Therefore, $35°C=95°F$