## Algebra 1: Common Core (15th Edition)

The distance from A to B: cos(27)=$\frac{5280}{x}$ x=$\frac{5280}{cos(27)}$=5925.88 The distance from B to C: tan(27)=$\frac{BC}{5280}$ BC=tan(27)(5280)=2690.29 Difference=AC+BC-AB=5280+2690.29-5925.88=2044.41 This is the closest to the answer choice, C.