Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Common Core End-of-Course Assessment - Page 795: 25


Simplify the expression $\frac{27a^{\frac{5}{2}}b^{\frac{4}{3}}}{9a^2b}$ Answer: $3a^{\frac{1}{2}}b^{\frac{1}{3}}$

Work Step by Step

Simplify $\frac{27a^{\frac{5}{2}}b^{\frac{4}{3}}}{9a^2b}$ 1. Divide the numbers $\frac{27}{9}=3$ 2. Simplify: $\frac{3a^{\frac{5}{2}}b^{\frac{4}{3}}}{a^2b}$ 3. Apply exponent rule:$\quad \frac{x^a}{x^b}\:=\:x^{a-b}$ 4. Simplify: $\frac{3a^{\frac{1}{2}}b^{\frac{4}{3}}}{b}$ 5. Apply the exponent rule: $\frac{x^a}{x^b}=x^{a-b}$ 6. Simplify: $3a^{\frac{1}{2}}b^{\frac{1}{3}}$
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