## Algebra 1: Common Core (15th Edition)

$y=-\frac{12}{x^{2}-2}$
2$x^{2}y-4y=-24$ Divide the equation by 2 a. $\frac{2x^{2}y}{2}=x^{2}y$ b. $\frac{-4y}{2}=-2y$ c.$\frac{-24}{2}=-12$ $x^{2}y-2y=-12$ The common term is y, so factor out y $y(x^{2}-2)=-12$ To find y divide $y(x^{2}-2)$ by $(x^{2}-2)$ $\frac{y(x^{2}-2)}{x^{2}-2}$= $y=-\frac{12}{x^{2}-2}$