Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - Get Ready! - Page 543: 23



Work Step by Step

$12y^2+8y-15$ $=12y^2+18y-10y-15$ $=(12y^2+18y)-(10y+15)$ $=6y(2y+3)-5(2y+3)$ $=(6y-5)(2y+3)$ Multiplying these two numbers would give us $12y^2+8y-15$
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