Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - Common Core Cumulative Standards Review - Selected Response - Page 610: 20

Answer

None

Work Step by Step

The discriminant decides how many real number solutions there are. $D = b^2 - 4ac$ If D is positive, there are 2 real number solution. If D is negative, there are 0 real number solutins. If D is 0, there is 1 real number solution. The equation of a quadratic equation is $ax^2 + bx + c = 0$. Here, $a = 2$, $b = 7$, and $c=9$. Plug that into the equation for the discriminant $D = 49 - 4*2*9$ $D = 49 - 72$ $D = -23$ D is negative, so there are no real number solutions.
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