Algebra 1: Common Core (15th Edition)

Answer choice A: $m^5p^{-4}$
The expression shown is the same thing as $(m^4 \times m^1) \times (n^{-1} \times n^1) \times (p^2 \times p^{-6})$. If you simplify, you will get $\boxed{m^5p^{-4}}$ The answer is $\boxed{A}$.