## Algebra 1: Common Core (15th Edition)

In order to solve the equation x2-25=0 we will factor the left side of the equation by applying the rule that states $a^2-b62=(a+b)(a-b)$ If we set $a^2=x^2$ and $b^2=25$, we can solve for a and b. $a^2=x^2$ After we square root both sides of the equation, we will get a=x $b^2=25$ After we square root both sides of equation, we will go b=5 Therefore, $x^2-25=(x+5)(x-5)$ And if $x^2-25=0$, then we can set x+5=0 and x-5=0 For x+5=0, we can solve for x by subtracting 5 from both sides of the equation, and getting x=-5 For x-5=0, we can solve for x by adding 5 to both sides of the equation, and getting x=5