Chapter 9 - Quadratic Functions and Equations - 9-8 Systems of Linear and Quadratic Equations - Practice and Problem-Solving Exercises - Page 599: 15

The solutions of the system are $(-1, 1)$ and $(2,4)$.

$y=x +2$ $y=x^2$ Substitute $x +2$ for y $x +2=x^2$ $x^2-x-2=0$ $(x+1)(x-2)=0$ $x+1=0$ or $x-2=0$ $x=-1$ or $x=2$ Find corresponding y-values. Use either original equation $y=x+2$ $y=(-1)+2$ or $y=(2)+2$ $y=1$ or $y=4$ The solutions of the system are $(-1, 1)$ and $(2,4)$.