Answer
The solutions of the system are $(6, 10)$ and $(-7,192)$.
Work Step by Step
Given: $y=-14x +94$
$y=x^2-13x+52$
$\rightarrow -14x +94=x^2-13x+52$
$x^2+x-42=0$
$(x-6)(x+7)=0$
$x=6$ or $x=-7$
Solve for y:
$y=-14(6) +94$ or $y=-14(-7) +94$
$y=10$ or $x=192$
The solutions of the system are $(6, 10)$ and $(-7,192)$.