Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-8 Systems of Linear and Quadratic Equations - Got It? - Page 597: 2

Answer

Days $=5$. People $=234$.

Work Step by Step

Pool A: $y=36x+54$. Pool B: $y=-x^2+39x+64$ Eliminate $y$ Subtract the two equations. $\Rightarrow y-y=36x+54-(-x^2+39x+64)$ Clear the parentheses. $\Rightarrow y-y=36x+54+x^2-39x-64$ Simplify. $\Rightarrow 0=x^2-3x-10$ Factor and solve. $\Rightarrow 0=(x-5)(x+2)$ Use the zero product property. $x-5=0$ or $x+2=0$ Solve for $x$. $x=5$ or $x=-2$ Eliminate the impossible solution. Substitute back $x=5$ into the original equation to find the value of $y$. Pool A: $\Rightarrow y=36(5)+54$ $\Rightarrow y=180+54$ $\Rightarrow y=234$ Pool B: $\Rightarrow y=-(5)^2+39(5)+64$ $\Rightarrow y=-25+195+64$ $\Rightarrow y=234$ Hence, the pools had the same attendance on Day $5$ with $234$ people.
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