Answer
$w=\pm \frac{2\sqrt 21}{3}-3$
Work Step by Step
$3w^2+18w-1=0$
$w^2+6w-\frac{1}{3}=0$
$(w+3)^2=\frac{28}{3}$
$w+3= \pm \frac{2\sqrt 21}{3}$
$w=\pm \frac{2\sqrt 21}{3}-3$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 9 - Quadratic Functions and Equations - 9-6 The Quadratic Formula and the Discriminant - Practice and Problem-Solving Exercises - Page 588: 57
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