Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-6 The Quadratic Formula and the Discriminant - Practice and Problem-Solving Exercises - Page 588: 57


$w=\pm \frac{2\sqrt 21}{3}-3$

Work Step by Step

$3w^2+18w-1=0$ $w^2+6w-\frac{1}{3}=0$ $(w+3)^2=\frac{28}{3}$ $w+3= \pm \frac{2\sqrt 21}{3}$ $w=\pm \frac{2\sqrt 21}{3}-3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.