Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-5 Completing the Square - Practice and Problem-Solving Exercises - Page 581: 63

Answer

$y^{29}$

Work Step by Step

Applying the rules of exponents: $y^8(y^{-7})^{-3}$ $=y^8(y^{(-7)\times(-3)})$ $=y^8y^{21}$ $=y^{29}$
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