Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-5 Completing the Square - Practice and Problem-Solving Exercises - Page 579: 17



Work Step by Step

$m^2+12m+19=0$ or, $m^2+12m=-19$ Compare it with the standard form of quadratic equation $ax^2+bx+c$, we have $a=1, b=12$ Therefore, $b^2=4ac$ $\implies$ $c=\dfrac{b^2}{4a}$ Thus, $c=\dfrac{b^2}{4a}=\dfrac{(12)^2}{4}=36$ To complete the square, add $4$ on both sides. $m^2+12m+36=-19+36$ $\implies (m+6)^2=17$ $\implies m+6=4.12$ and $\implies m+6=-4.12$ or, $m=-10.12,-1.88$
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