Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-5 Completing the Square - Practice and Problem-Solving Exercises - Page 579: 12



Work Step by Step

$q^2-4q+c$ Compare it with the standard form of quadratic equation $ax^2+bx+c$, we have $a=1, b=-4$ It will have discriminant, $d$ with formula : $d=b^2-4ac$ Since, $d=0$ for repeated root of the expression. Therefore, $b^2=4ac$ $\implies$ $c=\dfrac{b^2}{4a}$ To complete the square, plug in $a=1, b=-4$. Thus, $c=\dfrac{b^2}{4a}=\dfrac{(-4)^2}{4}=4$
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