Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-4 Factoring to Solve Quadratic Equations - Practice and Problem-Solving Exercises - Page 572: 41


The equation has two solutions, $x=0$ or $x=3$

Work Step by Step

We are given $3x^3-9x^2=0$ $3x^2(x-3)=0$ $x^2(x-3)=0$ $x=0$ or $x-3=0$ $\rightarrow x=3$ Therefore, the equation has two solutions, $x=0$ or $x=3$.
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