Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-1 Quadratic Graphs and Their Properties - Practice and Problem-Solving Exercises - Page 551: 39

Answer

Vertex: (0,3) Axis of Symmetry: x = 0

Work Step by Step

$Y = \frac{1}{4} x^{2} +3$ To find vertex: Use: $\frac{-b}{2a}$ to find the x cordinate In this case $\frac{-b}{2a}$ = $\frac{-0}{2*(1/4)}$ which = 0 Then plug the x cordinate (0) in to get the y cordinate: $Y = \frac{1}{4} 0^{2} +3$ $Y = 0+3$ $Y = 0$ So vertex = (0,3) Axis of Symmetry = the x cordinate So Axis of Symmetry is x = 0
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.