## Algebra 1: Common Core (15th Edition)

$Y = \frac{1}{4} x^{2} +3$ To find vertex: Use: $\frac{-b}{2a}$ to find the x cordinate In this case $\frac{-b}{2a}$ = $\frac{-0}{2*(1/4)}$ which = 0 Then plug the x cordinate (0) in to get the y cordinate: $Y = \frac{1}{4} 0^{2} +3$ $Y = 0+3$ $Y = 0$ So vertex = (0,3) Axis of Symmetry = the x cordinate So Axis of Symmetry is x = 0