## Algebra 1: Common Core (15th Edition)

To graph the given equation we calculate the domain and range and plot the points. We calculate the range for the values x= -3, 0, 3 $y=2/3x^2$ x=-3 $y=23(−3)2$ y=2/3(−3)(−3) y=6 x=0 $y=2/3(0)^2$ y=2/3(0)(0) y=0 x=3 $y=2/3(3)^2$ y=2/3(3)(3) y=6 (-3,6) (0,0) (3, 6) We plot the points and connect the graph to get the final graph