Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Common Core Cumulative Standards Review - Selected Response - Page 541: 9

Answer

(A) $5x-2y=14$.

Work Step by Step

The standard slope intercept form is $\Rightarrow y=mx+c$ Option (A):-$5x-2y=14$ $\Rightarrow y=\frac{5}{2}x-7$ $m=\frac{5}{2}$ For the $x-$intercept, substitute $y=0$. $\Rightarrow 0=\frac{5}{2}x-7$ Solve for $x$. $\Rightarrow \frac{14}{5}=x$ Hence, Option (A) is correct. Option (B):-$-5x-2y=14$ $\Rightarrow y=-\frac{5}{2}x-7$ $m=-\frac{5}{2}$ For the $x-$intercept, substitute $y=0$. $\Rightarrow 0=-\frac{5}{2}x-7$ Solve for $x$. $\Rightarrow -\frac{14}{5}=x$ Hence, Option (B) is not correct. Option (C):-$-5x+2y=14$ $\Rightarrow y=\frac{5}{2}x+7$ $m=\frac{5}{2}$ For the $x-$intercept, substitute $y=0$. $\Rightarrow 0=\frac{5}{2}x+7$ Solve for $x$. $\Rightarrow -\frac{14}{5}=x$ Hence, Option (C) is not correct. Option (D):-$5x+2y=-14$ $\Rightarrow y=-\frac{5}{2}x-7$ $m=-\frac{5}{2}$ For the $x-$intercept, substitute $y=0$. $\Rightarrow 0=-\frac{5}{2}x-7$ Solve for $x$. $\Rightarrow -\frac{14}{5}=x$ Hence, Option (D) is not correct.
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