## Algebra 1: Common Core (15th Edition)

Answer choice $H$: $\boxed{27x^3y^3}$
$(3y)^{-2}$ is the same thing as $\frac{1}{(3y)^2}$. $\frac{1}{\frac{1}{x}}$ is the same thing as $x$. Therefore, $\frac{3x^3y}{\frac{1}{(3y)^2}}$ is the same thing as, $3x^3y \times 9y^2$. The answer is $\boxed{27x^3y^3}$