Answer
Answer choice $H$: $\boxed{27x^3y^3}$
Work Step by Step
$(3y)^{-2}$ is the same thing as $\frac{1}{(3y)^2}$.
$\frac{1}{\frac{1}{x}}$ is the same thing as $x$. Therefore,
$ \frac{3x^3y}{\frac{1}{(3y)^2}}$ is the same thing as, $3x^3y \times 9y^2$.
The answer is $\boxed{27x^3y^3}$
