Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Chapter Test - Page 539: 21

Answer

$h(h^2+4)(7h-4)$

Work Step by Step

$7h^4-4h^3+28h^2-16h$ $=(7h^4+28h^2)-(4h^3+16h)$ $=7h^2(h^2+4)-4h(h^2+4)$ $=(h^2+4)(7h^2-4h)$ $=h(h^2+4)(7h-4)$
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