Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Lesson Check - Page 531: 2



Work Step by Step

$6d^{3}$+$3d^{2}$-10d-5.Factor out: You have four terms so group the first two and last two terms: ($6d^{3}$+$3d^{2}$)-(10d-5.) The GCF for the first group is $3d^{2}$ and for the second group it is -5: $3d^{2}$(2d+1)-5(2d+1) You have 2d+1 in common so group it by itself: (2d+1)($3d^{2}$-5)
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