Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Lesson Check - Page 526: 5


Perfect square, $(9r-5)^{2}$.

Work Step by Step

$81r^{2}-90r+25=$ ...write first and last terms as squares. $=(9r)^{2}-90r+(5)^{2}$ ...does the middle term equal $2ab$? $90r=2\cdot(9r)\cdot(5)$ $=(9r)^{2}-2\cdot(9r)\cdot(5)+(5)^{2}$ ...write as the square of a binomial. $=(9r-5)^{2}$ Perfect square, $(9r-5)^{2}$.
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