Answer
Two different values are $12$ and $15$.
Factors are
$(3g+2)(3g+2)$ and $(3g+1)(3g+4)$.
Work Step by Step
The given expression is
$9g^2+\_g+4$
The standard form of the trinomial is
$ax^2+bx+c$
Where, $a=9,c=4$ and $b=?$.
Multiply $a$ and $c$.
$ac=9\times 4=36$
Two possible factors are $6\times 6$ and $12\times 3$.
So the values of $b$ are $6+6=12$ and $12+3=15$.
The first trinomial is
$\Rightarrow 9g^2+12g+4$
Factor.
$\Rightarrow (3g+2)(3g+2)$.
The second trinomial is
$\Rightarrow 9g^2+15g+4$
Factor.
$\Rightarrow (3g+1)(3g+4)$.
