Answer
$(2w+3)(2w-1)$
Work Step by Step
Find factors of $ac$ that have a sum of $b$.
Since $ac=-12$ and $b=4$,
find factors of $-12 $ with a sum of $4$.
$\left[\begin{array}{lll}
\text{Factors of -12 } & \text{Sum of factors} & \\
1\text{ and }-12 & -11 & \\
-1\text{ and }12 & 11 & \\
-2\text{ and }6 & 4 & \text{...what we needed}
\end{array}\right]$
$4w^{2}+4w-3$
...use the factors to rewrite $bx$.
$=4w^{2}-2w+6w-3$
...factor out the GCF out of each pair of terms.
$=2w(2w-1)+3(2w-1)$
...use the Distributive Property.
$=(2w+3)(2w-1)$
